1) Display the details of all employees
SQL>Select * from emp;
2) Display the depart information from
department table
SQL>select * from dept;
3) Display the name and job for all the
employees
SQL>select ename,job from emp;
4) Display the name and salary for all the employees
SQL>select ename,sal from emp;
5) Display the employee no and
totalsalary for all the employees
SQL>select empno,ename,sal,comm, sal+nvl(comm,0) as"total salary" from
emp
6) Display the employee name and annual
salary for all employees.
SQL>select ename, 12*(sal+nvl(comm,0)) as "annual Sal" from
emp
7) Display the names of all the
employees who are working in depart number 10.
SQL>select emame from emp where deptno=10;
8) Display the names of all the
employees who are working as clerks and
drawing a salary more than 3000.
SQL>select ename from emp where job='CLERK' and sal>3000;
9) Display the employee number and
name who are earning comm.
SQL>select empno,ename from emp where comm is not null;
10) Display the employee number and
name who do not earn any comm.
SQL>select empno,ename from emp
where comm is null;
11) Display the names of employees who
are working as clerks,salesman or
analyst and drawing a salary more than
3000.
SQL>select ename from emp where job='CLERK' OR JOB='SALESMAN'
OR JOB='ANALYST' AND SAL>3000;
12) Display the names of the employees
who are working in the company for
the past 5 years;
SQL>select ename from emp where to_char(sysdate,'YYYY')-to_char(hiredate,'YYYY')>=5;
13) Display the list of employees who
have joined the company before
30-JUN-90 or after 31-DEC-90.
a)select ename from emp where hiredate
< '30-JUN-1990' or hiredate >
'31-DEC-90';
14) Display current Date.
SQL>select sysdate from dual;
15) Display the list of all users in
your database(use catalog table).
SQL>select username from all_users;
16) Display the names of all tables
from current user;
SQL>select tname from tab;
17) Display the name of the current
user.
SQL>show user
18) Display the names of employees
working in depart number 10 or 20 or 40
or employees working as
CLERKS,SALESMAN or ANALYST.
SQL>select ename from emp where
deptno in(10,20,40) or job
in('CLERKS','SALESMAN','ANALYST');
19) Display the names of employees
whose name starts with alaphabet S.
SQL>select ename from emp where
ename like 'S%';
20) Display the Employee names for
employees whose name ends with alaphabet S.
SQL>select ename from emp where
ename like '%S';
21) Display the names of employees
whose names have second alphabet A in
their names.
SQL>select ename from emp where
ename like '_A%';
22) select the names of the employee
whose names is exactly five characters
in length.
SQL>select ename from emp where
length(ename)=5;
23) Display the names of the employee
who are not working as MANAGERS.
SQL>select ename from emp where job
not in('MANAGER');
24) Display the names of the employee
who are not working as SALESMAN OR
CLERK OR ANALYST.
SQL>select ename from emp where job
not
in('SALESMAN','CLERK','ANALYST');
25) Display all rows from emp table.The
system should wait after every
screen full of informaction.
SQL>set pause on
26) Display the total number of
employee working in the company.
SQL>select count(*) from emp;
27) Display the total salary beiging
paid to all employees.
SQL>select sum(sal) from emp;
28) Display the maximum salary from emp
table.
SQL>select max(sal) from emp;
29) Display the minimum salary from emp
table.
SQL>select min(sal) from emp;
30) Display the average salary from emp
table.
SQL>select avg(sal) from emp;
31) Display the maximum salary being
paid to CLERK.
SQL>select max(sal) from emp where
job='CLERK';
32) Display the maximum salary being
paid to depart number 20.
SQL>select max(sal) from emp where
deptno=20;
33) Display the minimum salary being
paid to any SALESMAN.
SQL>select min(sal) from emp where
job='SALESMAN';
34) Display the average salary drawn by
MANAGERS.
SQL>select avg(sal) from emp where
job='MANAGER';
35) Display the total salary drawn by
ANALYST working in depart number 40.
SQL>select sum(sal) from emp where
job='ANALYST' and deptno=40;
36) Display the names of the employee
in order of salary i.e the name of
the employee earning lowest salary should salary appear first.
SQL>select ename from emp order by
sal;
37) Display the names of the employee
in descending order of salary.
a)select ename from emp order by sal
desc;
38) Display the names of the employee
in order of employee name.
a)select ename from emp order by ename;
39) Display empno,ename,deptno,sal sort
the output first base on name and
within name by deptno and with in deptno
by sal.
SQL>select empno,ename,deptno,sal
from emp order by
40) Display the name of the employee
along with their annual salary(sal*12).The name of the employee earning highest
annual salary should apper first.
SQL>select ename,sal*12 from emp
order by sal desc;
41) Display name,salary,hra,pf,da,total
salary for each employee. The
output should be in the order of total
salary,hra 15% of salary,da 10% of salary,pf 5%
salary,total salary will
be(salary+hra+da)-pf.
SQL>select ename,sal,sal/100*15 as
hra,sal/100*5 as pf,sal/100*10 as
da, sal+sal/100*15+sal/100*10-sal/100*5
as total from emp;
42) Display depart numbers and total
number of employees working in each
department.
SQL>select deptno,count(deptno)from
emp group by deptno;
43) Display the various jobs and total
number of employees within each job
group.
SQL>select job,count(job)from emp
group by job;
44) Display the depart numbers and
total salary for each department.
SQL>select deptno,sum(sal) from emp
group by deptno;
45) Display the depart numbers and max
salary for each department.
SQL>select deptno,max(sal) from emp
group by deptno;
46) Display the various jobs and total
salary for each job
SQL>select job,sum(sal) from emp
group by job;
47) Display the various jobs and total
salary for each job
SQL>select job,min(sal) from emp
group by job;
48) Display the depart numbers with
more than three employees in each dept.
SQL>select deptno,count(deptno) from
emp group by deptno having
count(*)>3;
49) Display the various jobs along with
total salary for each of the jobs
where total salary is greater than
40000.
SQL>select job,sum(sal) from emp
group by job having sum(sal)>40000;
50) Display the various jobs along with
total number of employees in each
job.The output should contain only
those jobs with more than three
employees.
SQL>select job,count(empno) from emp
group by job having count(job)>3
51) Display the name of the empployee
who earns highest salary.
SQL>select ename from emp where
sal=(select max(sal) from emp);
52) Display the employee number and
name for employee working as clerk and
earning highest salary among clerks.
SQL>select empno,ename from emp
where where job='CLERK'
and sal=(select max(sal) from
emp where job='CLERK');
53) Display the names of salesman who
earns a salary more than the highest
salary of any clerk.
SQL>select ename,sal from emp where
job='SALESMAN' and sal>(select
max(sal) from emp
where job='CLERK');
54) Display the names of clerks who
earn a salary more than the lowest
salary of any salesman.
SQL>select ename from emp where
job='CLERK' and sal>(select min(sal)
from emp
where job='SALESMAN');
Display the names of employees who earn
a salary more than that of
Jones or that of salary grether than that of scott.
SQL>select ename,sal from emp where
sal>
(select sal from emp where
ename='JONES')and sal> (select sal from emp
where ename='SCOTT');
55) Display the names of the employees
who earn highest salary in their
respective departments.
SQL>select ename,sal,deptno from emp
where sal in(select max(sal) from
emp group by deptno);
56) Display the names of the employees
who earn highest salaries in their
respective job groups.
SQL>select ename,sal,job from emp
where sal in(select max(sal) from emp
group by job)
57) Display the employee names who are
working in accounting department.
SQL>select ename from emp where
deptno=(select deptno from dept where
dname='ACCOUNTING')
58) Display the employee names who are
working in Chicago.
SQL>select ename from emp where
deptno=(select deptno from dept where
LOC='CHICAGO')
59) Display the Job groups having total
salary greater than the maximum
salary for managers.
SQL>SELECT JOB,SUM(SAL) FROM EMP
GROUP BY JOB HAVING SUM(SAL)>(SELECT
MAX(SAL) FROM EMP WHERE JOB='MANAGER');
60) Display the names of employees from
department number 10 with salary
grether than that of any employee
working in other department.
SQL>select ename from emp where
deptno=10 and sal>any(select sal from
emp where deptno not in 10).
61) Display the names of the employees
from department number 10 with
salary greater than that of all
employee working in other departments.
SQL>select ename from emp where
deptno=10 and sal>all(select sal from
emp where deptno not in 10).
62) Display the names of the employees
in Uppercase.
SQL>select upper(ename)from emp
63) Display the names of the employees
in Lowecase.
SQL>select lower(ename)from emp
64) Display the names of the employees
in Propercase.
SQL>select initcap(ename)from emp;
65) Display the length of Your name
using appropriate function.
SQL>select length('name') from dual
66) Display the length of all the
employee names.
SQL>select length(ename) from emp;
67) select name of the employee
concatenate with employee number.
SQL>select ename||empno from emp;
68) User appropriate function and
extract 3 characters starting from 2
characters from the following string 'Oracle'. i.e the out put should be
'ac'.
SQL>select substr('oracle',3,2) from
dual
69) Find the First occurance of
character 'a' from the following string i.e
'Computer Maintenance Corporation'.
SQL>SELECT INSTR('Computer
Maintenance Corporation','a',1) FROM DUAL
70) Replace every occurance of
alphabhet A with B in the string Allens(use
translate function)
SQL>select
translate('Allens','A','B') from dual
71) Display the informaction from emp
table.Where job manager is found it
should be displayed as boos(Use replace
function).
SQL>select
replace(JOB,'MANAGER','BOSS') FROM EMP;
72) Display empno,ename,deptno from emp
table.Instead of display department
numbers display the related department
name(Use decode function).
SQL>select
empno,ename,decode(deptno,10,'ACCOUNTING',20,'RESEARCH',30,'SALES',40,'OPRATIONS')
from emp;
73) Display your age in days.
SQL>select
to_date(sysdate)-to_date('10-sep-77')from dual
74) Display your age in months.
SQL>select
months_between(sysdate,'10-sep-77') from dual
75) Display the current date as 15th
Augest Friday Nineteen Ninety Saven.
SQL>select to_char(sysdate,'ddth
Month day year') from dual
76) Display the following output for
each row from emp table.
scott has joined the company on
wednesday 13th August ninten nintey.
SQL>select ENAME||' HAS JOINED THE
COMPANY ON '||to_char(HIREDATE,'day
ddth Month year')
from EMP;
77) Find the date for nearest saturday
after current date.
SQL>SELECT
NEXT_DAY(SYSDATE,'SATURDAY')FROM DUAL;
78) Display current time.
SQL>select to_char(sysdate,'hh:MM:ss')
from dual.
79) Display the date three months
Before the current date.
SQL>select add_months(sysdate,3)
from dual;
80) Display the common jobs from
department number 10 and 20.
SQL>select job from emp where
deptno=10 and job in(select job from emp
where deptno=20);
81) Display the jobs found in
department 10 and 20 Eliminate duplicate jobs.
SQL>select distinct(job) from emp
where deptno=10 or deptno=20
(or)
SQL>select distinct(job) from emp
where deptno in(10,20);
82) Display the jobs which are unique
to department 10.
SQL>select distinct(job) from emp
where deptno=10
83) Display the details of those who do
not have any person working under them.
SQL>select e.ename from emp,emp e
where emp.mgr=e.empno group by
e.ename having count(*)=1;
84) Display the details of those
employees who are in sales department and
grade is 3.
SQL>select * from emp where
deptno=(select deptno from dept where
dname='SALES')and sal between(select
losal from salgrade where grade=3)and
(select
hisal from salgrade where grade=3);
85) Display those who are not managers
and who are managers any one.
i)display the managers names
SQL>select distinct(m.ename) from
emp e,emp m where m.empno=e.mgr;
ii)display the who are not managers
SQL>select ename from emp where
ename not in(select distinct(m.ename)
from emp e,emp m where m.empno=e.mgr);
86) Display those employee whose name
contains not less than 4 characters.
SQL>select ename from emp where
length(ename)>4;
87) Display those department whose name
start with "S" while the location
name ends with "K".
SQL>select dname from dept where
dname like 'S%' and loc like '%K';
88) Display those employees whose
manager name is JONES.
SQL>select p.ename from emp e,emp p
where e.empno=p.mgr and
e.ename='JONES';
89) Display those employees whose
salary is more than 3000 after giving 20%
increment.
SQL>select ename,sal from emp where
(sal+sal*.2)>3000;
90) Display all employees while their
dept names;
SQL>select ename,dname from emp,dept
where emp.deptno=dept.deptno
91) Display ename who are working in
sales dept.
SQL>select ename from emp where
deptno=(select deptno from dept where
dname='SALES');
92) Display employee
name,deptname,salary and comm for those sal in between
2000 to 5000 while location is chicago.
SQL>select ename,dname,sal,comm from
emp,dept where sal between 2000
and 5000
and loc='CHICAGO' and emp.deptno=dept.deptno;
93)Display those employees whose salary
greter than his manager salary.
SQL>select p.ename from emp e,emp p
where e.empno=p.mgr and p.sal>e.sal
94) Display those employees who are
working in the same dept where his
manager is work.
SQL>select p.ename from emp e,emp p
where e.empno=p.mgr and
p.deptno=e.deptno;
95) Display those employees who are not
working under any manager.
SQL>select ename from emp where mgr
is null
96) Display grade and employees name
for the dept no 10 or 30 but grade is
not 4 while joined the company before
31-dec-82.
SQL>select ename,grade from
emp,salgrade where sal between losal and
hisal and deptno in(10,30) and grade<>4 and
hiredate<'31-DEC-82';
97) Update the salary of each employee
by 10% increment who are not
eligiblw for commission.
SQL>update emp set
sal=sal+sal*10/100 where comm is null;
98) SELECT those employee who joined
the company before 31-dec-82 while
their dept location is newyork or Chicago.
SQL>SELECT
EMPNO,ENAME,HIREDATE,DNAME,LOC FROM EMP,DEPT
WHERE (EMP.DEPTNO=DEPT.DEPTNO)AND
HIREDATE <'31-DEC-82' AND DEPT.LOC
IN('CHICAGO','NEW YORK');
99) DISPLAY EMPLOYEE
NAME,JOB,DEPARTMENT,LOCATION FOR ALL WHO ARE WORKING
AS MANAGER?
SQL>select ename,JOB,DNAME,LOCATION
from emp,DEPT where mgr is not
null;
100) DISPLAY THOSE EMPLOYEES WHOSE
MANAGER NAME IS JONES? --
[AND ALSO DISPLAY THEIR MANAGER NAME]?
SQL> SELECT P.ENAME FROM EMP E, EMP
P WHERE E.EMPNO=P.MGR AND
E.ENAME='JONES';
101) Display name and salary of ford if
his salary is equal to hisal of his
grade
a)select ename,sal,grade from
emp,salgrade where sal between losal and
hisal
and ename ='FORD' AND HISAL=SAL;
102) Display employee name,job,depart
name ,manager name,his grade and make
out an under department wise?
SQL>SELECT
E.ENAME,E.JOB,DNAME,EMP.ENAME,GRADE FROM EMP,EMP
E,SALGRADE,DEPT
WHERE EMP.SAL BETWEEN LOSAL AND HISAL
AND EMP.EMPNO=E.MGR
AND EMP.DEPTNO=DEPT.DEPTNO ORDER BY DNAME
103) List out all employees
name,job,salary,grade and depart name for every
one in the company except 'CLERK'.Sort on salary display the
highest salary?
SQL>SELECT ENAME,JOB,DNAME,SAL,GRADE
FROM EMP,SALGRADE,DEPT WHERE
SAL BETWEEN LOSAL AND HISAL AND
EMP.DEPTNO=DEPT.DEPTNO AND JOB
NOT IN('CLERK')ORDER BY SAL ASC;
104) Display the employee name,job and
his manager.Display also employee who
are without manager?
SQL>select e.ename,e.job,eMP.ename
AS Manager from emp,emp e where
emp.empno(+)=e.mgr
105) Find out the top 5 earners of
company?
SQL>SELECT DISTINCT SAL FROM EMP E
WHERE 5>=(SELECT COUNT(DISTINCT SAL)
FROM
EMP A WHERE A.SAL>=E.SAL)ORDER BY
SAL DESC;
106) Display name of those employee who
are getting the highest salary?
SQL>select ename from emp where
sal=(select max(sal) from emp);
107) Display those employee whose
salary is equal to average of maximum and
minimum?
SQL>select ename from emp where
sal=(select max(sal)+min(sal)/2 from
emp);
108) Select count of employee in each
department where count greater than 3?
SQL>select count(*) from emp group
by deptno having count(deptno)>3
109) Display dname where at least 3 are
working and display only department
name?
SQL>select distinct d.dname from
dept d,emp e where d.deptno=e.deptno
and 3>any
(select count(deptno) from emp group
by deptno)
110) Display name of those managers
name whose salary is more than average
salary of his company?
SQL>SELECT E.ENAME,EMP.ENAME FROM
EMP,EMP E
WHERE EMP.EMPNO=E.MGR AND
E.SAL>(SELECT AVG(SAL) FROM EMP);
111)Display those managers name whose
salary is more than average salary of
his employee?
SQL>SELECT DISTINCT EMP.ENAME FROM
EMP,EMP E WHERE
E.SAL <(SELECT AVG(EMP.SAL) FROM
EMP
WHERE EMP.EMPNO=E.MGR GROUP BY
EMP.ENAME) AND
EMP.EMPNO=E.MGR;
112) Display employee name,sal,comm and
net pay for those employee
whose net pay is greter than or equal
to any other employee salary of
the company?
SQL>select
ename,sal,comm,sal+nvl(comm,0) as NetPay from emp
where sal+nvl(comm,0) >any (select
sal from emp)
113) Display all employees names with
total sal of company with each
employee name?
SQL>SELECT ENAME,(SELECT
SUM(SAL) FROM EMP) FROM EMP;
114) Find out last 5(least)earners of
the company.?
SQL>SELECT DISTINCT SAL FROM EMP E
WHERE
5>=(SELECT COUNT(DISTINCT SAL)
FROM EMP A WHERE
A.SAL<=E.SAL)
ORDER BY SAL DESC;
115) Find out the number of employees
whose salary is greater than their
manager salary?
SQL>SELECT E.ENAME FROM EMP ,EMP E
WHERE EMP.EMPNO=E.MGR
AND EMP.SAL<E.SAL;
116) Display those department where no
employee working?
SQL>select dname from emp,dept where
emp.deptno not in(emp.deptno)
117) Display those employee whose
salary is ODD value?
SQL>select * from emp where
sal<0;
118) Display those employee whose
salary contains alleast 3 digits?
SQL>select * from emp where
length(sal)>=3;
119) Display those employee who joined
in the company in the month of Dec?
SQL>select ename from emp where
to_char(hiredate,'MON')='DEC';
120) Display those employees whose name
contains "A"?
SQL>select ename from emp where
instr(ename,'A')>0;
or
SQL>select ename from emp where
ename like('%A%');
121) Display those employee whose
deptno is available in salary?
SQL>select emp.ename from emp, emp e
where emp.sal=e.deptno;
122) Display those employee whose first
2 characters from hiredate -last 2
characters of salary?
SQL>select
ename,SUBSTR(hiredate,1,2)||ENAME||substr(sal,-2,2) from emp
123) Display those employee whose 10%
of salary is equal to the year of
joining?
SQL>select ename from emp where
to_char(hiredate,'YY')=sal*0.1;
124) Display those employee who are
working in sales or research?
SQL>SELECT ENAME FROM EMP WHERE
DEPTNO IN(SELECT DEPTNO FROM DEPT WHERE
DNAME IN('SALES','RESEARCH'));
125) Display the grade of jones?
SQL>SELECT ENAME,GRADE FROM
EMP,SALGRADE
WHERE SAL BETWEEN LOSAL AND HISAL
AND Ename='JONES';
126) Display those employees who joined
the company before 15 of the month?
a)select ename from emp where
to_char(hiredate,'DD')<15;
127) Display those employee who has
joined before 15th of the month.
a)select ename from emp where
to_char(hiredate,'DD')<15;
128) Delete those records where no of
employees in a particular department
is less than 3.
SQL>delete from emp where
deptno=(select deptno from emp
group by deptno having
count(deptno)<3);
129) Display the name of the department
where no employee working.
SQL> SELECT
E.ENAME,E.JOB,M.ENAME,M.JOB FROM EMP E,EMP M
WHERE E.MGR=M.EMPNO
130) Display those employees who are
working as manager.
SQL>SELECT M.ENAME MANAGER FROM EMP
M ,EMP E
WHERE E.MGR=M.EMPNO GROUP BY M.ENAME
131) Display those employees whose
grade is equal to any number of sal but
not equal to first number of sal?
SQL> SELECT ENAME,GRADE FROM
EMP,SALGRADE
WHERE GRADE NOT IN(SELECT
SUBSTR(SAL,0,1)FROM EMP)
132) Print the details of all the
employees who are Sub-ordinate to BLAKE?
SQL>select emp.ename from emp, emp e
where emp.mgr=e.empno and
e.ename='BLAKE';
133) Display employee name and his
salary whose salary is greater than
highest average of department number?
SQL>SELECT SAL FROM EMP WHERE
SAL>(SELECT MAX(AVG(SAL)) FROM EMP
GROUP BY DEPTNO);
134) Display the 10th record of emp
table(without using rowid)
SQL>SELECT * FROM EMP WHERE
ROWNUM<11
MINUS
SELECT
* FROM EMP WHERE ROWNUM<10
135) Display the half of the ename's in
upper case and remaining lowercase?
SQL>SELECT
SUBSTR(LOWER(ENAME),1,3)||SUBSTR(UPPER(ENAME),3,LENGTH(ENAME))
FROM EMP;
136) Display the 10th record of emp
table without using group by and rowid?
SQL>SELECT * FROM EMP WHERE
ROWNUM<11
MINUS
SELECT
* FROM EMP WHERE ROWNUM<10
Delete
the 10th record of emp table.
SQL>DELETE FROM EMP WHERE
EMPNO=(SELECT EMPNO FROM EMP WHERE ROWNUM<11
MINUS
SELECT
EMPNO FROM EMP WHERE ROWNUM<10)
137) Create a copy of emp table;
SQL>create table new_table as select
* from emp where 1=2;
138) Select ename if ename exists more
than once.
SQL>select ename from emp e group by ename having
count(*)>1;
139) Display all enames in reverse
order?(SMITH:HTIMS).
SQL>SELECT REVERSE(ENAME)FROM EMP;
140) Display those employee whose
joining of month and grade is equal.
SQL>SELECT ENAME FROM EMP WHERE SAL
BETWEEN
(SELECT LOSAL FROM SALGRADE WHERE
GRADE=TO_CHAR(HIREDATE,'MM')) AND
(SELECT HISAL FROM SALGRADE WHERE
GRADE=TO_CHAR(HIREDATE,'MM'));
141) Display those employee whose
joining DATE is available in deptno.
SQL>SELECT ENAME FROM EMP WHERE
TO_CHAR(HIREDATE,'DD')=DEPTNO
142) Display those employees name as
follows
A ALLEN
B BLAKE
SQL> SELECT SUBSTR(ENAME,1,1),ENAME
FROM EMP;
143) List out the employees
ename,sal,PF(20% OF SAL) from emp;
SQL>SELECT ENAME,SAL,SAL*.2 AS PF
FROM EMP;
144) Create table emp with only one
column empno;
SQL>Create table emp as select empno
from emp where 1=2;
145) Add this column to emp table ename
vrachar2(20).
SQL>alter table emp add(ename
varchar2(20));
146) Oops I forgot give the primary key
constraint. Add in now.
SQL>alter table emp add primary
key(empno);
147) Now increase the length of ename
column to 30 characters.
SQL>alter table emp modify(ename
varchar2(30));
148) Add salary column to emp table.
SQL>alter table emp add(sal
number(10));
149) I want to give a validation saying
that salary cannot be greater 10,000
(note give a name to this constraint)
SQL>alter table emp add constraint
chk_001 check(sal<=10000)
150) For the time being I have decided
that I will not impose this validation.My boss has agreed to pay more than
10,000.
SQL>again alter the table or drop
constraint with alter table emp drop
constraint chk_001 (or)Disable the constraint by using alter table emp modify constraint chk_001
disable;
151) My boss has changed his mind. Now he doesn't want to pay more than
10,000.so revoke that salary
constraint.
SQL>alter table emp modify
constraint chk_001 enable;
152) Add column called as mgr to your
emp table;
SQL>alter table emp add(mgr
number(5));
153) Oh! This column should be related
to empno. Give a command to add this
constraint.
SQL>ALTER TABLE EMP ADD CONSTRAINT
MGR_DEPT FOREIGN KEY(MGR) REFERENCES
EMP(EMPNO)
154) Add deptno column to your emp
table;
SQL>alter table emp add(deptno
number(5));
155) This deptno column should be
related to deptno column of dept table;
SQL>alter table emp add constraint
dept_001 foreign key(deptno)
reference dept(deptno)
[deptno
should be primary key]
156) Give the command to add the
constraint.
SQL>alter table <table_name) add
constraint <constraint_name>
<constraint type>
157) Create table called as
newemp. Using single command create this
table
as well as get data into this table(use
create table as);
SQL>create table newemp as select *
from emp;
SQL>Create table called as
newemp. This table should contain only
empno,ename,dname.
SQL>create table newemp as select
empno,ename,dname from emp,dept where
1=2;
158) Delete the rows of employees who
are working in the company for more
than 2 years.
SQL>delete from emp where
(sysdate-hiredate)/365>2;
159) Provide a commission(10% Comm Of
Sal) to employees who are not earning
any commission.
SQL>select sal*0.1 from emp where
comm is null
160) If any employee has commission his
commission should be incremented by
10% of his salary.
SQL>update emp set comm=sal*.1 where
comm is not null;
161) Display employee name and
department name for each employee.
SQL>select empno,dname from emp,dept
where emp.deptno=dept.deptno
162)Display employee number,name and
location of the department in which he
is working.
SQL>select empno,ename,loc,dname
from emp,dept where
emp.deptno=dept.deptno;
163) Display ename,dname even if there
are no employees working in a
particular department(use outer join).
SQL>select ename,dname from emp,dept
where emp.deptno=dept.deptno(+)
164) Display employee name and his
manager name.
SQL>select p.ename,e.ename from emp
e,emp p where e.empno=p.mgr;
165) Display the department name and
total number of employees in each
department.
SQL>select dname,count(ename) from
emp,dept where
emp.deptno=dept.deptno group by dname;
166)Display the department name along
with total salary in each department.
SQL>select dname,sum(sal) from
emp,dept where emp.deptno=dept.deptno
group by dname;
167) Display itemname and total sales
amount for each item.
SQL>select itemname,sum(amount) from
item group by itemname;
168) Write a Query To Delete The
Repeted Rows from emp table;
SQL>Delete from emp where rowid not
in(select min(rowid)from emp group
by ename)
169) TO DISPLAY 5 TO 7 ROWS FROM A
TABLE
SQL>select ename from emp
where rowid in(select rowid from emp where rownum<=7
minus
select rowid from empi where rownum<5)
170) DISPLAY
TOP N ROWS FROM TABLE?
SQL>SELECT * FROM
(SELECT
* FROM EMP ORDER BY ENAME DESC)
WHERE ROWNUM <10;
171) DISPLAY TOP 3 SALARIES FROM EMP;
SQL>SELECT SAL FROM ( SELECT * FROM EMP ORDER BY SAL DESC )
WHERE ROWNUM <4
172) DISPLAY 9th FROM THE EMP TABLE?
SQL>SELECT ENAME FROM EMP
WHERE ROWID=(SELECT ROWID FROM EMP WHERE
ROWNUM<=10
MINUS
SELECT ROWID FROM EMP WHERE ROWNUM
<10)
select
second max salary from emp;
select
max(sal) fromemp where sal<(select
max(sal) from emp);
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